[PSUBS-MAILIST] new submarine inside to outside hydraulic

[Dan H.]

Nope!  Just experienced...... LOL   Ben there
  ----- Original Message ----- 
  From: swaters 
  To: Personal Submersibles General Discussion 
  Sent: Saturday, April 12, 2014 6:47 PM
  Subject: Re: [PSUBS-MAILIST] new submarine inside to outside hydraulic


  Dan,
  You are brilliant!
  Thanks,
  Scott Waters








  Sent from my U.S. Cellular© Smartphone

  "Dan H." <jumachine at comcast.net> wrote:
  How to solve the problem of depth figuring in on the situation is to use 
  double ended cylinders.  With a rod of the same size sticking out of each 
  end of each cylinder the effect of water pressure balances out.  The force 
  is the same in either direction.

  Dan H.

  ----- Original Message ----- 
  From: "hank pronk" <hanker_20032000 at yahoo.ca>
  To: "Personal Submersibles General Discussion" 
  <personal_submersibles at psubs.org>
  Sent: Saturday, April 12, 2014 8:58 AM
  Subject: Re: [PSUBS-MAILIST] new submarine inside to outside hydraulic


  Hi Carsten,
  I am not sure about your math, I get a much different figure.
  A 1/2 in rod has an area of .19in
  multiply by 1,000 foot depth salt water 445psi = 87.33 lbs
  With a 10 to 1 lever that would be 8.7 lbs to push with your arm.
  Also you want a smaller cylinder inside with a longer stroke and you get an 
  even lighter load on your arm.
  Hank

  Subject: Re: [PSUBS-MAILIST] new submarine inside to outside hydraulic
  To: "Personal Submersibles General Discussion" 
  <personal_submersibles at psubs.org>
  Received: Saturday, April 12, 2014, 2:56 AM





  E-Mail Software 6.0

  Hi Scott,

  1 bar = 0,1
  N/mm2

  1000 meter depth = 100 bar or 10 N/mm2
  (or 1
  kg/mm2)

  A Hydraulic stamp of a 1/2 inch has a surface of 126

  mm2
  means the outside waterpressure on the cylinder stamp is
  1267
  N or
  127 Kg or 0,13 ts.

  If you make a drawing of your schematic you
  will see
  that it is not selfcompensating.
  Means you need a inside force of
  that
  amout just to compensate.
  If you asume you can take a pressure
  of 0,013
  ts
  with some comfore by hand you inside zylinder piston has to
  be
  the 10
  times more diameter thn the outside one.

  By the way the same
  force works
  on your troughulls cables of the same diameter.

  vbr Carsten




  <swaters at waters-ks.com> schrieb:

  I have a question maybe someone can answer.
  If you have two hydraulic cylinders that are completely
  filled with
  oil (no air pockets anywhere in the system) one in a
  submarine and on
  outside of a submarine. Each cylinder has the rod side
  connected to the
  head side of the other cylinder so when on rod extends, the
  flow of one
  makes the other cylinder do the same exact thing. Would the
  one cylinder
  that does the same as the other cylinder on the surface
  function the
  same way at depth? Or would the deeper you go the more force
  you would
  have trying to push the rod into the cylinder?

  Thanks,
  Scott Waters




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